Problem
ALG-B1-M02-P001 Common Factor with a Second Step
#1
★☆☆☆☆ Level 1 of 5
Factor \(6x^3y-9x^2y^2+3xy^3\).
First factor out \(3xy\), then factor the quadratic trinomial.
Factor out \(3xy\): \(6x^3y-9x^2y^2+3xy^3=3xy(2x^2-3xy+y^2)\).
Then \(2x^2-3xy+y^2=(2x-y)(x-y)\). Hence the full factorisation is \(3xy(2x-y)(x-y)\).
A basic exercise, but with a required second step.