Problem
ALG-B1-M10-P001 Minimum
#1
★☆☆☆☆ Level 1 of 5
Find the least value of \(x^2-10x+29\).
Complete the square.
\(x^2-10x+29=(x-5)^2+4\). The minimum is \(4\), attained at \(x=5\).
A short warm-up on completing the square.