Problem
COM-B1-M02-P006 Two Not Together
#6
★★☆☆☆ Level 2 of 5
In how many ways can \(6\) people stand in a row if two specified people must not stand together?
Subtract cases where they are together.
There are \(6!=720\) total arrangements. They stand together in \(2\cdot5!=240\) ways. Therefore the answer is \(720-240=480\).
Complement of the block problem.