Problem
NT-B1-M04-P003 Inverse of 5 Modulo 12
#3
★☆☆☆☆ Level 1 of 5
Find the inverse of \(5\) modulo \(12\).
Check \(5\cdot5\).
\(5\cdot5=25\equiv1\pmod{12}\). Therefore the inverse of \(5\) modulo \(12\) is \(5\).
Shows that an element may be its own inverse.