Problem
NT-B1-M04-P007 Six Solutions
#7
★★☆☆☆ Level 2 of 5
Solve \(6x\equiv12\pmod{18}\).
After reduction, the modulus becomes \(3\).
Divide \(6,12,18\) by \(6\): \(x\equiv2\pmod3\). Modulo \(18\), these are the classes \(2,5,8,11,14,17\).
Classic problem against incorrect division.