Problem
NT-B1-M09-P003 Prime Powers
#3
★☆☆☆☆ Level 1 of 5
How many positive divisors does \(2^5\cdot3^3\) have?
Choose the exponent of \(2\) and the exponent of \(3\).
The exponent of \(2\) can be chosen in \(6\) ways, and the exponent of \(3\) in \(4\) ways. Total: \(6\cdot4=24\) divisors.
No need to expand the number.