Problem
ALG-B1-M04-P001 A Linear Factor
#1
★☆☆☆☆ Level 1 of 5
The polynomial \(P(x)=x^3-2x^2-5x+6\) has root \(1\). Factor \(P(x)\).
Divide by \(x-1\).
Since \(P(1)=0\), \(P(x)\) is divisible by \(x-1\). Division gives \(P(x)=(x-1)(x^2-x-6)=(x-1)(x-3)(x+2)\).
Basic application of the factor theorem.