Problem
ALG-B3-M11-P005 Step Two
#5
★★★★☆ Level 4 of 5
Let \(f(n+2)=f(n)+8\), \(f(0)=1\), and \(f(1)=5\). Find \(f:\mathbb Z\to\mathbb Z\).
Separate even and odd arguments.
For \(n=2k\), \(f(n)=1+8k=4n+1\). For \(n=2k+1\), \(f(n)=5+8k=4n+1\). The answer is \(f(n)=4n+1\).
Discrete method among FE tasks.