Problem
GEO-B2-M05-P001 Find the Image of a Point
#1
★★☆☆☆ Level 2 of 5
An inversion has centre \(O\) and radius \(8\). Point \(A\) satisfies \(OA=5\). Find \(OA'\).
Use \(OA \cdot OA'=R^2\).
We have \(OA \cdot OA'=8^2=64\). Thus \(5\cdot OA'=64\), so \(OA'=\frac{64}{5}\).
A basic check of the definition.