Problem
GEO-B2-M07-P001 Area and Base
#1
★★☆☆☆ Level 2 of 5
In triangle \(ABC\), point \(D\in BC\), \(BD:DC=4:7\). Find \([ABD]:[ADC]\).
Triangles \(ABD\) and \(ADC\) have a common altitude from \(A\).
The areas are in the ratio of the bases on line \(BC\). Therefore \([ABD]:[ADC]=BD:DC=4:7\).
A basic application of a common altitude.