Problem
GEO-B2-M07-P002 From Area to Segment
#2
★★☆☆☆ Level 2 of 5
In triangle \(ABC\), point \(D\in BC\), and \([ABD]:[ADC]=5:2\). Find \(BD:DC\).
Again use the common altitude from \(A\).
Triangles \(ABD\) and \(ADC\) have a common altitude, so the ratio of areas equals the ratio of bases. Hence \(BD:DC=5:2\).
A check of the reverse transition.