Problem
NT-B1-M03-P010 Last Digit of \(7^{2026}\)
#10
★★☆☆☆ Level 2 of 5
Find the last digit of \(7^{2026}\).
The last-digit cycle of powers of \(7\) has length \(4\).
The cycle is \(7,9,3,1\). Since \(2026\equiv2\pmod4\), take the second digit of the cycle. The answer is \(9\).
Short exercise on periodicity of powers.