Problem
NT-B1-M04-P010 Incompatible System
#10
★★☆☆☆ Level 2 of 5
Prove that the system \(x\equiv2\pmod6\), \(x\equiv3\pmod9\) has no solutions.
Compare both conditions modulo \(3\).
The first condition gives \(x\equiv2\pmod3\). The second gives \(x\equiv0\pmod3\). These cannot hold simultaneously. No solutions exist.
Compatibility check before computation.