Problem
NT-B1-M08-P010 Incompatible System
#10
★★☆☆☆ Level 2 of 5
Prove that \(x\equiv4\pmod6\), \(x\equiv9\pmod{10}\) has no solutions.
Compare both conditions modulo \(2\).
From \(x\equiv4\pmod6\), \(x\) is even. From \(x\equiv9\pmod{10}\), \(x\) is odd. Contradiction. No solutions exist.
Another quick compatibility test.