Problem
NT-B1-M09-P016 Divisors of \(360^2\)
#16
★★★☆☆ Level 3 of 5
Find \(\tau(360^2)\).
Do not compute \(360^2\); double the exponents.
\(360=2^3\cdot3^2\cdot5\). Then \(360^2=2^6\cdot3^4\cdot5^2\), so \(\tau(360^2)=7\cdot5\cdot3=105\).
Connection with squares and odd \(\tau\).