Problem
NT-B1-M10-P003 Last Digit of a Power
#3
★☆☆☆☆ Level 1 of 5
Find the last digit of \(3^{2026}\).
The last digits of powers of \(3\) have period \(4\).
The last digits are \(3,9,7,1\), then the cycle repeats. Since \(2026\equiv2\pmod4\), the last digit is \(9\).
The simplest task on a residue cycle.