Problem
NT-B2-M03-P002 Order of Three
#2
★★☆☆☆ Level 2 of 5
Find \( \operatorname{ord}_{11}(3) \).
The powers must first reach \(1\).
\(3,9,27,81,243\) modulo \(11\) give \(3,9,5,4,1\). Therefore \( \operatorname{ord}_{11}(3)=5 \).
Point out that \(5\mid10\), as expected for a prime modulus.