Problem
NT-B2-M06-P001 The Difference \(10^n-1\)
#1
★★☆☆☆ Level 2 of 5
Find \(v_3(10^{2025}-1)\).
Use \(3\mid10-1\).
By LTE, \(v_3(10^{2025}-1)=v_3(10-1)+v_3(2025)=v_3(9)+4=2+4=6\).
Basic direct application.